SOLUTION: Factor completely: y^3-8 Thank you for your help and time !!!

Question 52755: Factor completely:
y^3-8
Thank you for your help and time !!!
Found 2 solutions by funmath, Nate:
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
The formula for factoring the difference of two perfect cubes is:

Therefore we have:

a=y and b=2 Plug them into your formula and you have:

Happy Calculating!!!
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
y^3 - 8
(y)^3 - (2)^3 = (y - 2)(y^2 + 2y + 4)
~> y^3 - 2y^2 + 2y^2 - 4y + 4y - 8 ~> y^3 - 8
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