SOLUTION: sketch the graph y=x(x-3)(x^2-1) finding additional points to sketch on the graph. I did: (x^2-3x)(x^2-1) = x^4-4x^2+3x i factored out difference of perfect squares with x^4-4x

Question 510318: sketch the graph y=x(x-3)(x^2-1) finding additional points to sketch on the graph.
I did: (x^2-3x)(x^2-1) = x^4-4x^2+3x
i factored out difference of perfect squares with x^4-4x^2 and got
x(x+2)(x-2) +3x = 0 (to get the x intercepts)
i got my y-int to be (0,0) and my x's to be x=+/-2 and x=0.
so idk if any of that is correct?
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
y = x*(x-3)*(x^2-1)
y = x*(x-3)*(x+1)*(x-1)
.
roots are x= -1, 0, 1,3
.

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