SOLUTION: solve the following equation using the complex number system: x^4 + 13x^2 +36 = 0 the math book i have doesn't show how to do these types of problems: very frustrating. th

Algebra.Com
Question 495360: solve the following equation using the complex number system:
x^4 + 13x^2 +36 = 0
the math book i have doesn't show how to do these types of problems: very frustrating.
the answers in the back of the book are (-2i, 2i, -3i, 3i)

Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
        x⁴+ 13x² + 36 = 0

Factor:

     (x² + 4)(x² + 9) = 0

x² + 4 =  0         x² + 9 = 0

    x² = -4             x² = -9
           __                  __ 
     x = ±Ö-4            x = ±Ö-9

     x = ±2i             x = ±3i 

Solutions: {-2i, 2i, -3i, 3i}

Edwin


RELATED QUESTIONS

Solve each equation in the complex number system. 1. x^4 = 16 2. x^4 + 13x^2 +... (answered by MathLover1,greenestamps)
Solve the equation in the complex number system. x^4 + 3x^2 - 4 = 0 (answered by josgarithmetic,timofer)
Please help me solve the equation in the complex number system... (answered by stanbon)
Solve and check each of the following problems using the substitution method. x=1/5y... (answered by solver91311)
Solve each equation in the complex number system. A. x^4 = 1 B. x^4 + 3x^2 - 4... (answered by math_tutor2020)
solve equation in the complex number system... (answered by Alan3354,Edwin McCravy)
Solve the equation in the complex number system.... (answered by solver91311)
{{{x+6y=2}}} {{{5x+4y=36}}} I have been trying to use substitution to solve the... (answered by jim_thompson5910)
The book doesn't say if I should either factor it solve it or both. But it has to be one... (answered by josgarithmetic,MathTherapy)