SOLUTION: I was asked to find the square root of my equation which is 4x^2-8x+4=56. I know that I should move the 4 to the other side so my equation would then be 4x^2-8x=52, and I know that

Question 481285: I was asked to find the square root of my equation which is 4x^2-8x+4=56. I know that I should move the 4 to the other side so my equation would then be 4x^2-8x=52, and I know that the square root of 4x^2 would be 2x and I know that the square root of 52 is 7.21, but what would be the square root of 8x? That is where I get lost.
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
4x^2-8x+4=56
4x2-8x-52=0
x2-2x-13=0

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=56 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 4.74165738677394, -2.74165738677394. Here's your graph:

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