SOLUTION: If the first and third of three consecutive odd integers are added together, the result is 63 less than five times the second integer. Find the third integer.

Question 46764: If the first and third of three consecutive odd integers are added together, the result is 63 less than five times the second integer. Find the third integer.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let x be the first odd integer, x+2 the next consecutive odd integer, and x+4 the third consecutive odd integer. From the problem description, you can write:
x + (x+4) = 5(x+2)-63 Simplify and solve for x.
2x+4 = 5x+10-63
2x+4 = 5x-53 Subtract 2x from both sides of the equation.
4 = 3x-53 Add 53 to both sides.
3x = 57 Divide both sides by 3.
x = 19
x+2 = 21
x+4 = 23
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