SOLUTION: 34. Find two consecutive integers such that the sum of 2 times the first integer and 7 times second integer is 88.

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Question 46139: 34. Find two consecutive integers such that the sum of 2 times the first integer and 7 times second integer is 88.

Answer by Earlsdon(6287) About Me  (Show Source):
You can put this solution on YOUR website!
Let the two numbers be x and (x+1). Write the equation from the problem.
2x%2B7%28x%2B1%29+=+88 Simplify and solve for x.
2x%2B7x%2B7+=+88
9x%2B7+=+88 Subtract 7 from both sides.
9x+=+81 Divide both sides by 9.
x+=+9 and x%2B1+=+10
Check:
2(9) + 7(10) = 18 + 70 = 88 It checks!