# SOLUTION: 34. Find two consecutive integers such that the sum of 2 times the first integer and 7 times second integer is 88.

Algebra ->  Algebra  -> Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: 34. Find two consecutive integers such that the sum of 2 times the first integer and 7 times second integer is 88.       Log On

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 Algebra: Complex Numbers Solvers Lessons Answers archive Quiz In Depth

 Question 46139: 34. Find two consecutive integers such that the sum of 2 times the first integer and 7 times second integer is 88. Answer by Earlsdon(6287)   (Show Source): You can put this solution on YOUR website!Let the two numbers be x and (x+1). Write the equation from the problem. Simplify and solve for x. Subtract 7 from both sides. Divide both sides by 9. and Check: 2(9) + 7(10) = 18 + 70 = 88 It checks!