SOLUTION: Divide
{{{(6z^4-4z^3+9z^2+4z+5)}}} / {{{(z^2-z+2)}}}
Algebra.Com
Question 44624: Divide
/
Answer by pvaka(23) (Show Source): You can put this solution on YOUR website!
(6z^4-4z^3+9z^2+4z+5)/(z^2-z+2)
(1)z^2-z+2 (6z^2)= 6z^4-6z^3+12z^2 substract from 6z^4-4z^3+9z^2+4z+5 = 2z^3-3z^2-4z+5
(2)z^2-z+2 (2z)=2z^3-2z^2+47 substract from 2z^3-3z^2-4z+5 = -z^2-8z+5
(3)z^2-z+2 (-1)=-z^2+z-2 substract from -z^2-8z+5 =-9z+7 REMAINDER
SOLUTION: 6z^2+2z-1+(-9z+7)/z^2-z+2
RELATED QUESTIONS
3z^-7+4z^-6+6z^-5+5z^-4+4z^-3+3z^-2+z^-1
(answered by Fombitz)
(4z+3)(z-2)
(answered by richwmiller)
z^2-4z=0 (answered by ankor@dixie-net.com,josgarithmetic,greenestamps,Alan3354)
x+2y-4z=2
y+z=5
z=3
(answered by jim_thompson5910)
Find the LCM
z^3+4z^2+4z, z^2-4z
(answered by jsmallt9)
Multiply... (answered by Cromlix)
Use a vertical format to find the product. Use FOIL.
{{{4z^3 + 6z^2 + 9z + 7}}}
(answered by Fombitz)
(z)/(2)=(4z^2)-1 (answered by stanbon)
Divide and simplify.... (answered by persian52)