SOLUTION: z1=(1-i)
z2=(1/2+√3/2 i)
multiply them to get z3
Algebra.Com
Question 436410: z1=(1-i)
z2=(1/2+√3/2 i)
multiply them to get z3
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Just use FOIL like multiplying any other binomials. Remember: 
John
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
z1=2+i
z2=-3+i... (answered by Edwin McCravy)
1. Given: Z1= 2-2i , Z2= 3i and Z3= -3+i .Find:
(c) Z1*Z3 (d) Z3xZ2 (e) the acute... (answered by prakharsingh406,ikleyn)
given that z1=2+i and z2=-3+4i and 1/z3=1/z1+1/z2. determine the value of z3 in standard... (answered by mananth,Edwin McCravy,math_tutor2020)
1. Given: Z1= 2-2i , Z2= 3i and Z3= -3+i . Solve analytically and illustrate graphically. (answered by proyaop)
1. Given: Z1= 2-2i , Z2= 3i and Z3= -3+i . Solve analytically and illustrate graphically. (answered by proyaop)
if z1=2+j, z2=3+j and z3=j3
what is the equivalent impedance z if z= z1 + z2 + z3... (answered by stanbon)
I have been asked to evaluate Z1 X Z2 AND Z1 / Z2 in Cartesian form where Z1 = 1-j3 and... (answered by Fombitz)
Z1=3e^i180/3
Z2=2e^i4*180/3
Z3=z1z2
Z1= -0.5 +0.866i
Z2=z1^3
Z1= -16... (answered by Alan3354)
If z1+z2+z3=0 and z1^2+z2^2+z3^2=0, prove that... (answered by Edwin McCravy)
