SOLUTION: 3(cos395+isin395) ----------- ----------- - 9(cos65+isin65)

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Question 420876: 3(cos395+isin395)
-------------------------
9(cos65+isin65)
Answer by jsmallt9(3759)   (Show Source): You can put this solution on YOUR website!
When posting fractions on Algebra.com, please
  1. Type a "(" (left parenthesis)
  2. Type the entire numerator
  3. Type ")/(" (the right parenthesis closes the numerator, the "/" represents the division, and the left parenthesis opens the denominator)
  4. Type the entire denominator
  5. Type a ")" (to close the denominator)

This makes the actual fraction easy to understand. When you post fractions the way you did this one, it can be difficult to read.

Putting arguments of function in parentheses helps, too. So your expression, posted this way, would be:
(3(cos(395)+isin(395)))/(9(cos(65)+isin(65)))


Dividing complex numbers written in polar form is fairly simple because there is a formula that makes it easy. For two complex numbers:

and

we can divide them using the formula:
(as long as is not zero).

Using this formula to divide your complex numbers we get:

which simplifies to

which is the answer in polar form. For standard form, a+bi, we replace the cos and sin with their values. 330 is a special angle so we don't need a calculator:

Distributing the 1/3 we get:

or
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