Hi

how do I find the vertex for X^2-3x-4=0? 

by completing the Square and putting into the vertex form

Note: the vertex form of a parabola,  where(h,k) is the vertex

x^2 - 3x - 4 = 0

 (x-3/2)^2 - 9/4  - 4 = 0

 (x-3/2)^2 - 25/4 = 0  vertex  is Pt(3/2,-25/4)



 

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