Question 417504: the area of a square is 45 more than the perimeter. find the length of a side :) Found 2 solutions by stanbon, ewatrrr:Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website! the area of a square is 45 more than the perimeter. find the length of a side :)
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area of a square = side^2
Perimeter of a square = 4*side
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Equation:
s^2 = 4s + 45
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s^2-4s-45 = 0
(s-9)(s+5) = 0
Positive solution:
side = 9 units
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Cheers,
Stan H.
==================== Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Hi
Let s represent the length of a side
Question states***
s^2 = 4s + 45
s^2 - 4s -45 = 0
factoring
(x+5)(x-9)=0
(x+5)= 0 x =-5 Tossing out negative solution for length
( x-9)= 0 x = 9, the length of a side
CHECKING our Answer***
81 = 36 + 45 = 81