Hi

finding the exact roots

x^3-8x^2+4x+48 = 0        |substitution show x = -2 is a solution

(x+2)(x^2-10x + 24)   |Dividing x^3-8x^2+4x+48  by (x+2)

factoring quadratic

(x+2)(x-6)(x-4) = 0 

Note:SUM of the inner product(-6x) and the outer product(-4x) = -10x

(x+2)(x-6)(x-4) = 0 

x = {-2,6,4} 

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