SOLUTION: what is the value of x in:
81^x+2 = 27^5x+4
Algebra.Com
Question 389791: what is the value of x in:
81^x+2 = 27^5x+4
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
81 = 3^4
27 = 3^3
--------
81^x+2 = 27^5x+4
4(x+2) = 3(5x+4)
4x+8 = 15x+12
x = -4/11
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