SOLUTION: o NEED TO WRITE A POLYNOMIAL FUNCTION OF LEAST DEGREE THAT HAS REAL COEFFICIENTS, THE GIVEN ZERO, AND LEADING COEFFICIENT OF 1. First problem gave me the zeros of 2, -2 and -6i

Question 377607: o NEED TO WRITE A POLYNOMIAL FUNCTION OF LEAST DEGREE THAT HAS REAL COEFFICIENTS, THE GIVEN ZERO, AND LEADING COEFFICIENT OF 1.
First problem gave me the zeros of 2, -2 and -6i
Therefore to start:
(X-2)(X+2)(X+6i)
I multiplied (X-2)(X+2) and got (x2 - 4)
next I multiplied (x2 - 4)(X+6i) using the FOIL method
x3 + 6x2i - 4x - 24i
I know that i2 = -1 and that i = rad -1 but don't know how to deal with the "i" in this problem to make it a polynomial function.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
If you have a complex root, then it's complex conjugate is also a root since complex roots only occur as complex conjugate pairs.

Take it from there to complete the expansion.

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