SOLUTION: square root 8i = a + bi (?)

Question 359079: square root 8i = a + bi (?)
Answer by Jk22(389) (Show Source): You can put this solution on YOUR website!
then (a+bi)*(a+bi) = 8i = a^2-b^2+2abi

hence a=+/-b, and

2ab=8, implies a=b, and 2a^2=8, a^2=4, a=+/-2=b

we have 2 solutions : (2+2i) and -(2+2i).

Verification : (2+2i)(2+2i)=4+4i+4i-4=8i
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