SOLUTION: with the calculus of residues show that the integration from (0 to 2pi ) for cos^n theta d theta = n!pi / ( 2^n-1(( n/2)!)^2).. with explaination of the steps ... pleeeeez..

Question 356696: with the calculus of residues show that
the integration from (0 to 2pi ) for
cos^n theta d theta = n!pi / ( 2^n-1(( n/2)!)^2)..
with explaination of the steps ... pleeeeez..
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Not sure how you would use the calculus of residues to do that.
You could use standard integration techniques with integration by parts and trignometric substitution.
Additionally, neither of these methods are for algebra problems.

RELATED QUESTIONS
Given that cos(theta) = m/n, find the value of cos^2(theta) -... (answered by stanbon)

show that the integration from ( 0 to infinity ) for ( cos 3x / ( x^2+1)^2 )= 2pi/e^3 (answered by Fombitz)

find the value of x for which the equation sin x=-1 is true a)2pi(n) b)pi/2 + 2pi(n) (answered by Fombitz)

Prove that for any n >= 2 , given {{{(sin(pi/n))*(sin(2pi/n))*"..."*(sin((n-1)pi/n)) =... (answered by Edwin McCravy)

Dear math teacher, I am having difficulties with the following problem: 4 times nC2 (answered by Theo)

I have tried this problem for rational equations and I am unable to get the "work shown"... (answered by scott8148)

Simplify: {{{ (sqrt (2) + sqrt (2) i )^3 }}} The answer should be in the form of {{{... (answered by tommyt3rd)

solve the equation cos theta - tan theta * cos theta = 0 for 0< theta < 2... (answered by stanbon,DrBeeee)

If 0 < n < 1, which of the following gives the correct ordering of √n, n, and, n^2 (answered by CharlesG2)