SOLUTION: in ax^2+bx+c form, what is 8-2x^2=(x+2)^2-7?
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Question 342733: in ax^2+bx+c form, what is 8-2x^2=(x+2)^2-7?
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
8-2x^2=(x+2)^2-7
8-2x^2=x^2+4x+4-7
0=x^2+4x+4-7+2x^2-8
0=3x^2+4x-11
3x^2+4x-11 <----- Answer
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