SOLUTION: 3(2i+3)(1+3i)

Question 340228: 3(2i+3)(1+3i)
Found 2 solutions by nyc_function, stanbon:
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
3(2i+3)(1+3i) =
NOTE: i^2 = -1
(6i + 9)(3i + 1) =
18i^2 + 6i + 27i + 9 =
18(-1) + 33i + 9 =
-18 + 33i + 9 =
-9 + 33i
Did you follow?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
3(2i+3)(1+3i)
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= 3[2i-6+3+9i]
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= 3[-3+11i]
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= -9+33i
============
Cheers,
Stan H.
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