SOLUTION: My problem says to solve each equation in the real number system. The problem says 2x^3+3x^2+2x+3=0. I factored the problem by grouping and came out with (2x^2+3)(x^2+1)=0, but w

Question 32244: My problem says to solve each equation in the real number system. The problem says 2x^3+3x^2+2x+3=0. I factored the problem by grouping and came out with (2x^2+3)(x^2+1)=0, but when I solve for x I come out with imaginary numbers and I am not supposed to. I would apprecaite any help you could give me in solving this problem. Thanks, Britta
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
My problem says to solve each equation in the real number system. The problem says 2x^3+3x^2+2x+3=0. I factored the problem by grouping and came out with (2x^2+3)(x^2+1)=0,
NO...DID YOU TYPE WRONGLY?2X+3 IS A FACTOR NOT 2X^2+3
X^2(2X+3)+1(2X+3)=(2X+3)(X^2+1)=0...SO THERE IS ONE SOLUTION IN REAL NUMBERS NAMELU...2X+3=0...OR...2X=-3...OR...X=-3/2=-1.5
but when I solve for x I come out with imaginary numbers and I am not supposed to. I would apprecaite any help you could give me in solving this problem. Thanks, Britta
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