SOLUTION: 10 / (3-i2) (10 divided by 3-i2)

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10/(3-i2)
Our goal is to eliminate any radical or non-real complex numbers from the denominator. We can do this by multiplying both numerator and denominator of the given expression with (3+i2).
This gives [10/(3-i2)](3+i2/3+i2)
= 10(3+2i)/[3^2-(i2)^2]
= 10(3+2i)/(9+4)
= 10(3+2i)/13