SOLUTION: If cost varies inversely as the square of the number purchased, and 5 can be purchased for $45, how much would 10 cost?

SOLUTION: If cost varies inversely as the square of the number purchased, and 5 can be purchased for $45, how much would 10 cost?

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Question 31759: If cost varies inversely as the square of the number purchased, and 5 can be purchased for $45, how much would 10 cost?
Answer by mukhopadhyay(490) (Show Source): You can put this solution on YOUR website!
Cost = k/(number)^2
So, 45 = k/25
=> k = 45*25
Cost for 10 would be
Cost = 45*25/10^2
=> Cost = 45*25/100 = 45/4 = $11.25
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