SOLUTION: I wondered how to check and see if my answer is correct. The problem is (3+4i)/4i, so I divided the 3 and 4i by 4i and ended up with 1+3/4i. Then I multiplied top and bottom by

Question 313420: I wondered how to check and see if my answer is correct.
The problem is (3+4i)/4i, so I divided the 3 and 4i by 4i and ended up with 1+3/4i. Then I multiplied top and bottom by -4i, and I got 1-12i/16, which reduced down to 1-3i/4. Is there a way to check and see if my answer is correct?
Found 2 solutions by CharlesG2, Fombitz:
Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
"I wondered how to check and see if my answer is correct.
The problem is (3+4i)/4i, so I divided the 3 and 4i by 4i and ended up with 1+3/4i. Then I multiplied top and bottom by -4i, and I got 1-12i/16, which reduced down to 1-3i/4. Is there a way to check and see if my answer is correct?"
(3 + 4i)/4i
3/(4i) + 4i/4i (should be equivalent to above line)
3/(4i) + 1
(3i)/(4i^2) + 1 (multiplied top and bottom of first term by i)
(3i)/(-4) + 1 (i^2 = -1)
(-3/4)i + 1
1 - (3/4)i (switched terms around so it would be in a + bi form)
check:
1 - (3/4)i
(4 - 3i)/4 (should be equivalent to above line)
(4i - 3i^2)/4i (multiplied top and bottom by i)
(4i + 3)/4i (i^2 = -1)
(3 + 4i)/4i (switched terms around so numerator would be in a + bi form)

Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!

Yes, you're correct.
Just reduce your answer to simplest terms.
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