SOLUTION: Which of these is the cube root of 1? 1/2- i sqrt3/2 1/2+ i sqrt3/2 -1/2 + i sqrt3/2 1- i sqrt3 1+ i sqrt3

Question 301200: Which of these is the cube root of 1?
1/2- i sqrt3/2
1/2+ i sqrt3/2
-1/2 + i sqrt3/2
1- i sqrt3
1+ i sqrt3

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!

x = 1
-----

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -3 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -3 is + or - .

The solution is , or
Here's your graph:

------------------------
It's -1/2 + i sqrt3/2
Also -1/2 - i sqrt3/2

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