SOLUTION: solve in simplest form: 2x^(2)+4x=-10 im lost on this one.. i thought you should add the -10 to the other side making it 2x^2+4x+10=0... then divide by 2 and it equals x^2+2x+5=

Question 298179: solve in simplest form: 2x^(2)+4x=-10
im lost on this one.. i thought you should add the -10 to the other side making it 2x^2+4x+10=0... then divide by 2 and it equals x^2+2x+5=0.. but since it doesnt fully factor then I get lost and unsure of what to do
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -64 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -64 is + or - .

The solution is

Here's your graph:

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -16 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -16 is + or - .

The solution is

Here's your graph:

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