SOLUTION: So this lesson is simplifying radical fractions and i can understand the simple ones obviously, but these just seem way too hard, i would try to show what i tried but i dont even k
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Question 282102: So this lesson is simplifying radical fractions and i can understand the simple ones obviously, but these just seem way too hard, i would try to show what i tried but i dont even know where to start. My teacher said to start by making a common denominator, and she told us the common denominator would be n(n+1). Sorry if you cant read it easily, but i tried.
Heres one of the hard ones i cant solve:
n+5-12/n+1
---------- <- that is a fraction bar
n+9/n+1-5/n
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
My advice to you: Start using parentheses -- lots of parentheses. I think you were trying to render:
I'll proceed on that assumption:
The LCD in the denominator is indeed )
. The LCD in the numerator is simply 
. So, first apply the LCDs:
\ +\ 5(n\,+\,1)\ -\ 12}{\frac{n(n\,+\,9)}{n(n\,+\,1)}\ -\ \frac{5(n\,+\,1)}{n(n\,+\,1)})
Distribute to eliminate parentheses:
}})
Collect like terms:
}})
Factor the two trinomials:
(n\,-\,1)} {\frac{(n\,+\,5)(n\,-\,1)}{n(n\,+\,1)}})
Invert and multiply:
(n\,-\,1)}{1}\ \cdot\ {\frac{n(n\,+\,1)}{(n\,+\,5)(n\,-\,1)})
Eliminate factors common to both numerator and denominator:
}{1}\ \cdot\ {\frac{n(n\,+\,1)}{(n\,+\,5)})
(n\,+\,1)}{(n\,+\,5)})
Remember to exclude any value that would cause any denominator to equal zero during the entire process. Hence the following values are excluded:
, 
, 
, and 
John
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