SOLUTION: how do u solve 7 + 5i / 8 - 7i in standard form?
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Question 281967: how do u solve 7 + 5i / 8 - 7i in standard form?
Found 3 solutions by Alan3354, CharlesG2, stanbon:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
how do u solve 7 + 5i / 8 - 7i in standard form?
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There's nothing to solve. It can be simplified is all, by eliminating the "i" in the denominator.
Multiply NUM and DEN by the conjugate of the DEN, 8 + 7i
--> (7+5i)*(8+7i)/(64 + 49)
= (56 - 35 + 89i)/113
= (21 + 89i)/113
Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
how do u solve 7 + 5i / 8 - 7i in standard form?
(7 + 5i)/(8 - 7i) * (8 + 7i)/(8 + 7i) (multiplied top and bottom by conjugate of the denominator)
[(7 + 5i)(8 + 7i)]/[(8 - 7i)(8 + 7i)]
(56 + 49i + 40i + 35i^2)/(64 + 56i - 56i - 49i^2)
(56 + 89i - 35)/(64 + 49)
(21 + 89i)/113
21/113 + (89/113)i
approx. 0.1858 + 0.7876i
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how do u solve (7 + 5i) / (8 - 7i) in standard form?
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Multiply numerator and denominator by (8+7i) to get:
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[(7+5i)(8+7i)]/[64+49]
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= [56-35 +89i]/113
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= [21+89i]/13
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Cheers,
Stan H.
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