# SOLUTION: write a quadratic equation having the given numbers as solutions. 3/5, -9

Algebra ->  Algebra  -> Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: write a quadratic equation having the given numbers as solutions. 3/5, -9      Log On

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 Algebra: Complex Numbers Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Complex Numbers Question 264075: write a quadratic equation having the given numbers as solutions. 3/5, -9Found 3 solutions by Greenfinch, JBarnum, karibet:Answer by Greenfinch(383)   (Show Source): You can put this solution on YOUR website!Equation is (x + 9)(5x - 3) = 0 which expands to 5x^2 + 42x - 27 = 0 Answer by JBarnum(2044)   (Show Source): You can put this solution on YOUR website!x=3/5, -9 x=3/5 5x=3 5x-3=0 x=-9 x+9=0 (5x-3)(x+9) 5x^2-3x+45x-27 5x^2+42x-27 Answer by karibet(1)   (Show Source): You can put this solution on YOUR website!5(x+9)+2= -5(x-1)-1