SOLUTION: write a quadratic equation having the given numbers as solutions. 3/5, -9

Question 264075: write a quadratic equation having the given numbers as solutions.
3/5, -9
Found 3 solutions by Greenfinch, JBarnum, karibet:
Answer by Greenfinch(383)   (Show Source): You can put this solution on YOUR website!
Equation is
(x + 9)(5x - 3) = 0 which expands to
5x^2 + 42x - 27 = 0
Answer by JBarnum(2146)   (Show Source): You can put this solution on YOUR website!
x=3/5, -9
x=3/5
5x=3
5x-3=0
x=-9
x+9=0
(5x-3)(x+9)
5x^2-3x+45x-27
5x^2+42x-27

Answer by karibet(1)   (Show Source): You can put this solution on YOUR website!
5(x+9)+2= -5(x-1)-1
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