SOLUTION: 3x(2x-5)(3x+1) = 0
Algebra.Com
Question 257597: 3x(2x-5)(3x+1) = 0
Answer by jmorgan22(8) (Show Source): You can put this solution on YOUR website!
3x(2x-5)(3x+1)=0
If any individual factor on the left-hand side of the equation is equal to 0, the entire expression will be equal to 0.
3x=0
(2x-5)=0
(3x+1)=0
Set the first factor equal to 0 and solve.
3x=0
Divide each term in the equation by 3.
3x/3=0/3
Simplify the left-hand side of the equation by canceling the common factors.
x=0/3
0 divided by any number or variable is 0.
x=0
Set the next factor equal to 0 and solve.
(2x-5)=0
Remove the parentheses around the expression 2x-5.
2x-5=0
Since -5 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 5 to both sides.
2x=5
Divide each term in the equation by 2.
2x/2=5/2
Simplify the left-hand side of the equation by canceling the common factors.
x=5/2
Set the next factor equal to 0 and solve.
(3x+1)=0
Remove the parentheses around the expression 3x+1.
3x+1=0
Since 1 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 1 from both sides.
3x=-1
Divide each term in the equation by 3.
3x/3=-1/3
Simplify the left-hand side of the equation by canceling the common factors.
x=-1/3
The final solution is all the values that make 3x(2x-5)(3x+1)=0 true.
Answer: x=0, 5/2, -1/3
RELATED QUESTIONS
3x-2x²+1=0 (answered by )
2x² -3x -1 =... (answered by alegriajoy33,Deina)
(x+5)(3x-1)+13=0... (answered by checkley71)
2x+5=3x-1 (answered by jim_thompson5910)
2x + 5 = 3x +... (answered by sheldonbbtrocks)
2x+5=3x+1 (answered by ReadingBoosters)
2x-1=3x+5 (answered by rfer)
3x+1+2x-5 (answered by rfer)
(3x+1)+(2x+5) (answered by stanbon)