SOLUTION: what is the solution set of (6x+4)squared=77

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Question 255207: what is the solution set of (6x+4)squared=77
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
(6x+4)squared=77
36x^2+48x+16-77=0
36x^2+48x-61=0

x=(-48+-sqrt[48^2-4*36*-61])/2*36
x=(-48+-sqrt[2,304+8,784])/72
x=(-48+-sqrt11,088)/72
x=(-48+-105.2996)/72
x=(-48+105.2996)/72
x=57.2996/72
x=.796 ans.
x=(-48-105.2996)/72
x=-153.2996/72
x=-2.129 ans.

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