SOLUTION: my problem are plz help me i need to see the work i need them solved by tonight plz 1) x^2-8x+15=0 2) x^2+2x-6=0 3) 2x^2+3x-5=0 4) 2x^2+7x+6=0 4) x^2-4x+5=

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Question 247920: my problem are plz help me i need to see the work
i need them solved by tonight plz
1) x^2-8x+15=0

2) x^2+2x-6=0

3) 2x^2+3x-5=0

4) 2x^2+7x+6=0

4) x^2-4x+5=0

5) x^2-10x+28=0
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
1) x^2-8x+15=0
(x-3)*(x-5) = 0
x = 3, x = 5
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2) x^2+2x-6=0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=28 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 1.64575131106459, -3.64575131106459. Here's your graph:

----------
x = -1 ± sqrt(7)
--------------
3) 2x^2+3x-5=0
do these like the ones above. If you can't factor them, use the quadratic equation. It always works.
-------------------
4) 2x^2+7x+6=0
4) x^2-4x+5=0
5) x^2-10x+28=0
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