SOLUTION: I wrote problem two ways: I think this one however, is the correct one f(x)=3x^2 + x - 5 f(x)=3x^2 + x

SOLUTION: I wrote problem two ways: I think this one however, is the correct one f(x)=3x^2 + x - 5 f(x)=3x^2 + x - 5 3x^2 + x -5 = 0

Question 246109: I wrote problem two ways: I think this one however, is the correct one
f(x)=3x^2 + x - 5
f(x)=3x^2 + x - 5
3x^2 + x -5 = 0

Answer by marcsam823(57) (Show Source): You can put this solution on YOUR website!
Since there is no easy way to factor this equation, use the quadratic formula:

the general formula for a quadratic is

Your equation is:

Therefore:
a=3
b=1
c=-5

Substitute and solve for x:

There are 2 answers: (this are the x -coordinates of the points where the parabola crosses the x-axis):

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