SOLUTION: I have to solve the complex number system: 4x^4+7x^2-2=0 I also have to then graph it including all x and y-intercepts. I tried using the quadratic equation, but the answers I go

Question 241711: I have to solve the complex number system: 4x^4+7x^2-2=0
I also have to then graph it including all x and y-intercepts. I tried using the quadratic equation, but the answers I got don't work, so I guess I'm doing it wrong. I also tried to solve it by completing the square, but that doesn't work either.
Step by step instructions would be very helpful.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
the y-intercept (when x equals zero), is -2

the x-intercept(s) are the real number roots

factoring ___ (4x^2 - 1) (x^2 + 2) = 0

factoring (difference of squares) ___ (2x + 1) (2x - 1) = 0 ___ x = � 1/2 ___ these are the x-intercepts

(x^2 + 2) = 0 gives 2 "imaginary" roots ___ x = � i√2

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