SOLUTION: prove 2^6cos^4teta(angle)sin^3teta(angle)=-sin7teta(angle)-sin5teta(angle)+3sin3teta(angle) 3sinteta(angle).

Algebra.Com
Question 234977: prove 2^6cos^4teta(angle)sin^3teta(angle)=-sin7teta(angle)-sin5teta(angle)+3sin3teta(angle)
3sinteta(angle).

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
prove 2^6cos^4teta(angle)sin^3teta(angle)=-sin7teta(angle)-sin5teta(angle)+3sin3teta(angle)
3sinteta(angle).
------------
That's not clear or decipherable.
2^6cos^4 ???

RELATED QUESTIONS

Given angle 1 = angle 4 Prove angle 2= angle... (answered by Alan3354)
Begin by stating what has been provided GIVEN: angle 1~= angle 2, angle 1~= angle 3... (answered by ikleyn)
Given: Angle 1 is compliment to angle 2. Prove: Angle ABC is a right angle. (answered by cleomenius,MathTherapy)
Given: Angle 1 is congruent to angle 3. Prove: Angle 2 is congruent to angle 4. (answered by Alan3354)
given: angle 1 is congruent to angle 2 prove: angle WOY is congruent to angle... (answered by math-vortex)
Angle 1 is congruent to angle 4. Prove angle 2 is supplementary to angle... (answered by ikleyn)
Given: Angle 1 is congruent to angle 3 Prove: angle 2 and angle 3 are supplementary (answered by Alan3354)
Angle AOC is a right angle Prove measure of angle 1 + measure of angle 2 =... (answered by ikleyn)
Given: angle 1 and angle 2 form a linear pair angle 2 + angle 3 + angle 4 = 180 (answered by solver91311)