SOLUTION: Find the polar form of the following expression: 3 sq root 2 - 3 sq root 2i?
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Question 226461: Find the polar form of the following expression: 3 sq root 2 - 3 sq root 2i?
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
^2+\left(-3\sqrt{2}\right)^2}=\sqrt{18+18}=\sqrt{36}=6)
. 
=\tan^{-1}\left(\frac{-3\sqrt{2}}{3\sqrt{2}}\right)=\tan^{-1}(-1)=-\frac{\pi}{4})
Polar Form: +i\sin\left(\theta\right)\right)=6\left(\cos\left(-\frac{\pi}{4}\right)+i\sin\left(-\frac{\pi}{4}\right)\right)=6\left(\frac{\sqrt{2}}{2}-i\frac{\sqrt{2}}{2}\right))
Answer: Polar form of 
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