SOLUTION: I need help with my algebra 2. We are doing stuff with negative exponents and notation. Please i need help. My grade is a 7%. HELP!!!!!!!!!

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Question 22511: I need help with my algebra 2. We are doing stuff with negative exponents and notation. Please i need help. My grade is a 7%. HELP!!!!!!!!!
Answer by AnlytcPhil(1806)   (Show Source): You can put this solution on YOUR website!
I need help with my algebra 2. We are doing stuff with negative exponents
and notation. Please i need help. My grade is a 7%. HELP!!!!!!!!!

To simplify a problem with negative exponents:

1. If a negative exponential occurs as a factor of a numerator, move the
   base and exponent from the numerator to the denominator and change the
   sign of the exponent to positive.

2. If a negative exponential occurs as a factor of a denominator, move the
   base and exponent from the denominator to the numerator and change the
   sign of the exponent to positive.

Example:

  2-1x3y-2
 ----------
  2-3x-2y3

Move the 2-1 from the numerator to the denominator and change the sign of
the exponent -1 to +1

     x3y-2
 ------------
  212-3x-2y3

Leave the x3 where it is since it already has a positive exponent. Move the
y-2 from numerator to denominator and change the sign of the exponent -2 to
+2:

       x3
 ---------------
   212-3x-2y3y2


Move the 2-3 from denominator to numerator and change the
sign of the exponent -3 to +3:

     23x3
  -----------
   21x-2y3y2

Move the x-2 from denominator to numerator and change the
sign of the exponent -2 to +2:

   23x3x2
  --------
   21y3y2

Now all the exponents are positive.  So we add the exponents of x3 and x2,
getting x5 in the numerator:

    23x5
  --------
   21y3y2

Now we add exponents of y3 and y2 getting y5 in the denominator

    23x5
  --------
    21y5

Now we subtract the exponents of 23 and 21, getting 22, placing the result
in the numerator because the larger exponent 3 is in the numerator:

    22x5
  --------
     y5

Finally we evaluate 22 as 4:

    4x5
  --------
     y5

Edwin
AnlytcPhil@aol.com

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