SOLUTION: How do I solve 2x^2-x-1=0 ? Thanks

Algebra.Com
Question 22428: How do I solve 2x^2-x-1=0 ? Thanks
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=9 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 1, -0.5. Here's your graph:

RELATED QUESTIONS

How do I solve 4(1/4x - 2) = 0?... (answered by Alan3354)
how do i solve... (answered by Jk22)
Hi, How do I solve this quadratic equation: 2-x = x^2 + 2x + 2?... (answered by Cromlix)
2x-2y+5=0 how do i solve this ? thanks! (answered by checkley75)
X^2 + 2X +1 = 81 How do I solve... (answered by Alan3354)
√(6x+1)= x-1 Solve. I got 6x+1=x^2-2x+1 Subtracted 6x and 1 and got 0=x^2-8x+0 (answered by stanbon,Nate)
Please help me. I am confused. How do I solve these by factoring? 3x^2 -2x = 0 and (answered by ankor@dixie-net.com)
#1) (2x-3) (4x+5)=0 #2) X to the second power -3x=0 How do I solve this? (answered by stanbon)
2x+3/x-1=10/X^2-1+2x-3/x+1 how do you solve this problem?... (answered by Fombitz,stanbon)