SOLUTION: Find the real-number solutions of the equation:{{{2x^3-6x^2=0}}}

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Question 22152: Find the real-number solutions of the equation:2x%5E3-6x%5E2=0
Answer by Earlsdon(6103) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
2x%5E3+-+6x%5E2+=+0 Factor 2x^2
2x%5E2%28x+-+3%29 Apply the zero product principle.
2x%5E2+=+0 and/or x+-+3+=+0
If 2x%5E2+=+0 then, x+=+0
If x+-+3+=+0 then, x+=+3
The solutions are:
x = 0 (A double root)
x = 3