You can
put this solution on YOUR website!6x + 5y +2z = 830
3x + 7y+4z=820
2z-22=x
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Since x is already given in terms of z (in the 3rd eqn), sub for x in the other 2 equations.
6x + 5y +2z = 830
3x + 7y+4z=820
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6(2z-22) + 5y + 2z = 830
5y + 14z = 962 Eqn A
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3(2z-22) + 7y + 4z = 820
7y + 10z = 886 Eqn B
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Get the same coefficient for y by multiplying Eqn A by 7 and Eqn B by 5
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35y + 98z = 5810 A times 7
35y + 50z = 4430 B times 5
---------------- Subtract
0y + 48z = 1380
z = 1380/48
z 115/4 One answer done
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Sub for z into Eqn A (or B, same result)
5y + 14z = 962 Eqn A
5y + 14*115/4 = 962
5y = 962 - 805/2 = 1119/2
y = 1119/10 = 111.9
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Sub for y and z into any of the 3 original eqns to find x
6x + 5y +2z = 830
6x + 5*1119/10 + 2*115/4 = 830
6x = 4260/6
x = 710
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You can
put this solution on YOUR website!Question #1
6x + 5y +2z = 830 ------ (i)
3x + 7y+4z=820 ---------(ii)
2z-22=x ---------------(iii)
HELP!
Substitute 2Z - 22 for x in eq (i)
6x + 5y +2z = 830
6(2z - 22) + 5y + 2z = 830
12z - 132 + 5y + 2z = 830
5y + 14z = 962 ---------- (iv)
Substitute 2Z - 22 for x in eq (ii)
3x + 7y + 4z = 820
3(2z - 22) + 7y + 4z = 820
6z - 66 + 7y + 4z = 820
7y + 10z = 886 ---------- (v)
We now have 2 equations with 2 variables
5y + 14z = 962 ---------- (iv)
7y + 10z = 886 ---------- (v)
35y + 98z = 6,734 ---------- (vi) ------ Multiplying eq (iv) by 7
- 35y - 50z = - 4,430 ---------- (vii)------ Multiplying eq (v) by - 5
Add eq (vi) and (vii) to get: 48z = 2,304
z =
=
Substitute 48 for z in eq (v): 7y + 10z = 886 ---------- 7y + 10(48) = 886
7y + 480 = 886
7y = 406
=
Substitute 48 for z in any of the equations, but I chose eq (iii) since it's the simplest to substitute in to calculate the value of x
2z - 22 = x
2(48) - 22 = x
96 - 22 = x
x =
