SOLUTION: how do you write the expression -2+4i/6+3i as a complex number in standard form?
Algebra.Com
Question 210457: how do you write the expression -2+4i/6+3i as a complex number in standard form?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Multiply the fraction by 1 in the form of the conjugate of the denominator divided by itself:
\left(\frac{6-3i}{6-3i}\right))
Apply FOIL to the numerator binomials and use the fact that the product of two conjugates is the difference of two squares (and remember that 
), then reduce to lowest terms:
}\ =\ \frac{30i}{45}\ =\ \frac{2i}{3})
But standard form is 
. Since there is no real part, 
. Therefore the properly constituted answer is:
i)
John
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