# SOLUTION: You build a box that is 4 feet long, 5 feet wide, and 8 feet high. The distance from the top left front corner to the top right back corner is_____feet.The distance from the bottom

Algebra ->  Algebra  -> Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: You build a box that is 4 feet long, 5 feet wide, and 8 feet high. The distance from the top left front corner to the top right back corner is_____feet.The distance from the bottom      Log On

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 Algebra: Complex Numbers Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Complex Numbers Question 20365: You build a box that is 4 feet long, 5 feet wide, and 8 feet high. The distance from the top left front corner to the top right back corner is_____feet.The distance from the bottom left front corner to the top right back corner is_____feet. Answer by kapilsinghi(68)   (Show Source): You can put this solution on YOUR website!Answer to first problem Consider the top of the box which is rectangle with width 5 feet and length 4 feet. we need to find the diagnol of this rectangle if we draw a diagnol of this rectangle then we have two right angled triangles for which we need to fing the hypotynuse so the diagnol will be Sqrt(5^2 + 4^2) = Sqrt(25 + 16) = Sqrt(41) = 6.4 Feet Solution to the Second Problem Now imagine to cut the box into two halves along the calculated diagnol in the above problem We will see a rectangle with width of 6.4 Feet and length of 8 Feet(height of the box) we need to find the diagnol again of this rectangle as we did in the above problem so the diagnol will be sqrt(8^2 + (6.4)^2) = Sqrt(64 + 41) = Sqrt(101)= 10.04 Feet kapilsinghi123@gmail.com