SOLUTION: Factor this equation 2c^3-5c^2+c+2

Algebra.Com
Question 19916: Factor this equation
2c^3-5c^2+c+2

Answer by longjonsilver(2297)   (Show Source): You can put this solution on YOUR website!


By trial and error, put values into the equation. This will lead us to find one of the factors... start with easy numbers like +1, -1 then +2 and -2 etc until you find one.

so, if c=1, we get that the polynomial is equal to zero, so c=1 is a solution (or root). If c=1, then (c-1)=0. Therefore, we can say that (c-1) is a factor.

You now need to perform long division of this factor into the polynomial to find the other factor. Doing this, gives .

So, the factors are . Factoring the quadratic gives the final answer:

jon.

RELATED QUESTIONS

(c^3-2c^2-5c+3)+(c^2+2c-1) (answered by jai_kos)
Factor completely. If prime, say so. 5c^2 + 2c -... (answered by mananth)
How do you solve this equation using Cramer's Rule? a.b.5c=2 3a+b+2c=3... (answered by oscargut)
i need to solve this equation {{{ 5c^2(c+10)-4c(2c^2-6c+1)... (answered by lizette763)
How to I know if I am doing this equation right ? 8c + 2 - 2c - 6 - 6c - 9 = 7c + 3 -... (answered by Alan3354,Maths68)
(c^2 - 5c + 6) /... (answered by mananth)
Please help me factor this equation: {{{ 6b^2c-12b^2c^3+3b^3c^2 }}}. (answered by 303795)
Factor the trinomial. {{{c^3-5c^2-24c}}} Factor... (answered by robertb)
c^2-2c-35=... (answered by ccs2011)