First, perform synthetic division on the polynomial using the test zero . Note: you can easily solve for "z" and find that one solution is
i | 1 0 0 i
| i -1 -i
-----------
1 i -1 0
Since the first three numbers in the third row are 1, i, and -1, this means that
Now simply use the quadratic formula to solve for "z":
Start with the quadratic formula
Plug in , , and
Square to get .
Multiply
Combine like terms.
So the other two solutions are or
===========================================================
Answer:
So the 3 solutions are , , or