SOLUTION: When two resistors S and T are connected in parallel their combined resistance R is given by the expression R=1/((1/S)+(1/T)) This expression can be rewritten as a ra

Question 19411: When two resistors S and T are connected in parallel their combined resistance R is given by the expression
R=1/((1/S)+(1/T))

This expression can be rewritten as a rational expression in S and T. The numerator of that expression is ST and its denominator is S+T

Suppose you connect two resistors of the same resistance in parallel. Then the resistance of the two connected resistors equals _________ times that of each resistor alone.

Answer by xcentaur(357) (Show Source): You can put this solution on YOUR website!
R=ST/(S+T)
Now if they have the same value,S=T
R=T*T(T+T)=(T^2/2T)
So the resistance would be (T^2/2T)

To find how many times it is greater than T alone,find the ratio:
Let the ratio be x

therefore our ratio is (1/2)

Thats your answer.
Hope this helps,
Prabhat

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