SOLUTION: You guys are great. Please help . Reduce /simplify the fractions or square root 1. 14/21 2. AB^2C/A^3BC 3.(x-2)(x-3)/2(x-3) 4.2x^2-2x-4/x^2-1 5. Square root

Question 192966: You guys are great. Please help . Reduce /simplify the fractions or square root
1. 14/21

2. AB^2C/A^3BC

3.(x-2)(x-3)/2(x-3)

4.2x^2-2x-4/x^2-1

5. Square root of 49

6. Square root of 18
7. 36/64 this question has line on the top and sides of both.
Found 2 solutions by jim_thompson5910, RAY100:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
# 1

Solved by pluggable solver: Reducing Fractions Calculator

In order to reduce , the numerator and denominator must share a common factor. This common number must evenly divide into both of them without any remainder or decimal.

In order to completely reduce the fraction, you must divide the numerator and the denominator by the greatest common factor (GCF). The GCF of and is AMP Parsing Error of []: Invalid expression '': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . (note: click here if you need help with finding the GCF). So divide both the numerator and denominator by AMP Parsing Error of []: Invalid expression '': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. .

In other words, to reduce the fraction you do this

AMP Parsing Error of [(14/)/(21/)]: Invalid expression ')/(21/)': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . Plug in the numerator, denominator, and the GCF

AMP Parsing Error of [(2)/(21/)]: Invalid expression ')': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . Now divide 14 by to get 2. This is now the new numerator.

Now divide 21 by to get 3. This is now the new denominator.

So

AMP Parsing Error of [(14/)/(21/)=2/3]: Invalid expression ')/(21/)=2/3': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. .

This means that reduces to

In other words,

# 2

Start with the given expression

Factor

Highlight the common terms.

Cancel out the common terms.

Simplify

Multiply

So where every variable CANNOT equal 0.

# 3

Start with the given expression

Highlight the common terms.

Cancel out the common terms.

Simplify

So where

# 4

Start with the given expression

Factor the numerator

Factor the denominator

Highlight the common terms.

Cancel out the common terms.

Simplify

Distribute

So where or

# 5

To find, , let's list the first few perfect squares. To find the perfect squares, just square 0 to get 0, square 1 to get 1, square 2 to get 4, square 3 to get 9, etc...

So the first few perfect squares are:

, , , , , , , , , ,

Notice that . Remember that the square root "undoes" a square. So or simply

# 6

Start with the given expression

The goal of simplifying expressions with square roots is to factor the radicand into a product of two numbers. One of these two numbers must be a perfect square. When you take the square root of this perfect square, you will get a rational number.

So let's list the factors of 18

Factors:
1, 2, 3, 6, 9, 18

Notice how 9 is the largest perfect square, so lets factor 18 into 9*2

Factor 18 into 9*2

Break up the square roots using the identity

Take the square root of the perfect square 9 to get 3

So the expression simplifies to

In other words,

----------------------------
Check:
Notice if we evaluate the square root of 18 with a calculator we get

and if we evaluate we get

This shows that . So this verifies our answer

# 7

I don't know what you mean here....

Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
1) 14/21 divide num & den by 7 =2/3
2) check if this is right problem
(a b^2c) / (a^3bc
to divide common bases, subtract exponents
taking one variable at a time
a^1/a^3 = a6(1-3) = a^(-2) = 1/(a^2)
b^2/b=b^(2-1)=b^1=b
c^1/c^1=c^(1-1)=c^0=1
recombining
answer = B/A^2
3) check to see if correct problem
((x-2)(x-3))/ (2(x-3))
(x-3)/(x-3)=1
(x-2)/2
4) ( 2x^2-2x-4)/(x^2-1)
factor numerator and denominator
((2)(x-2)(x+1))/((x+1)(x-1))
(x+1)/(x+1)=1
(2(x-2))/(x-1)
5) sqrt49=+/- 7
6) sqrt18=sqrt(9*2)=sqrt9*sqrt2=+/- 3sqrt2
7) (36)/(64) dive num & den by 4 = 9/16
RELATED QUESTIONS
please help me simplify the following fraction:... (answered by Fombitz)
simplify/Reduce 16 4 _______ - ___ x^2+2x-3 x+3 (answered by mbarugel)
(x^2+2x)/4x-3/(6x^3)/(8x^2-2x-3) simplify and reduce....please... (answered by stanbon)
Please simplify. 4 x the square root of -3 + 2 x the square root of... (answered by stanbon)
Reduce the fractions to lowest terms.... (answered by TakeATuition.com)
Can you please help me with these questions? I am stuck! 1. Simplify completely. 5x - (answered by edjones)
I have plugged this one into the solver and that confused me even more. Solve by... (answered by tutor_paul,HyperBrain)
Divide: x^2 � 3x + 2 / 7x � 14 � x^2 � 1 / 7x + 7 Thank You!!! You guys are (answered by edjones,jim_thompson5910)
Solve 8x^2 + 2x - 3 = 0 Reduce fractions to lowest terms. a) x = 3/4 or x = -3/4 b) x (answered by Miceandwine)