# SOLUTION: This question came from an exam paper in Australia: Solve: z^2=3+5i I presume that the question requires an answer in the form z = a + bi I have tried, but I end up getting a sq

Algebra ->  Algebra  -> Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: This question came from an exam paper in Australia: Solve: z^2=3+5i I presume that the question requires an answer in the form z = a + bi I have tried, but I end up getting a sq      Log On

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 Click here to see ALL problems on Complex Numbers Question 189153: This question came from an exam paper in Australia: Solve: z^2=3+5i I presume that the question requires an answer in the form z = a + bi I have tried, but I end up getting a square root of a square root for an exact answer, or approx. +1.1897 or -1.1897 for b and approx. +2.1013 or -2.1013 for a. I obtained this by letting z = a + bi, and therefore z^2 = a^2 + 2abi -b^2, and therefore a^2 - b^2 equals 3, and 2ab equals 5, and then solving these two simultaneous equations. Is there a simpler way, please? Answer by Alan3354(30993)   (Show Source): You can put this solution on YOUR website!Use the Argand diagram. --> = (34)^(1/4)cis(29.52) = ~ 2.415cis(29.52)