SOLUTION: 1.3+i√5 ________ 3-i√5 2.4-i√2 __________ i√2

Algebra.Com
Question 179620: 1.3+i√5
________
3-i√5






2.4-i√2
__________
i√2

Answer by Mathtut(3670)   (Show Source): You can put this solution on YOUR website!
I will do one. and get you started on the other.. you must multiply by the conjugate to get rid of the complex number in the denominator
:
1.3+i√5/3-i√5
:so we have
:
so the conjugate of is
:

:

:

:
:
:
2.4-i√2/i√2 the conjugate for this is repeat what took place in the problem I just solved...multiplying both top and bottom by the conjugate

RELATED QUESTIONS

i am asked to multiply (√[3] + 4√[5])(2√[3] –... (answered by checkley77)
I need help mulitplying this: (√[6] + 2√[2])(4√[6] – 3√[2]) (answered by jim_thompson5910)
simplify these showing all work please, dont skip any steps. 1. √-36 2.... (answered by robertb)
Multiply: (5√[2] + 3)(√[2] – 2√[3]) (answered by stanbon,MathLover1)
Multiply: (5√[2] + 3)(√[2] – 2√[3]) (answered by Fombitz)
Express the given number in terms of i. 5√-100 1/2√-16... (answered by geetha_rama)
5. Multiply: (√[6] + 2√[2])(4√[6] – 3√[2]) (answered by stanbon)
5. Multiply: (√[6] + 2√[2])(4√[6] – 3√[2]) (answered by stanbon)
multiply (8√[6] + 3√[2])(4√[6] – 5√[2]) (answered by Fombitz,stanbon)
Multiply: (8√[6] + 3√[2])(4√[6] – 5√[2])... (answered by MathLover1)