SOLUTION: 4-2i ÷ 3+i -5-3i ÷ 2-2i

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Question 179579: 4-2i ÷ 3+i


-5-3i ÷ 2-2i

Answer by Mathtut(3670)   (Show Source): You can put this solution on YOUR website!

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I will do one. and get you started on the other.. you must multiply by the conjugate to get rid of the complex number in the denominator
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1.3+i√5/3-i√5
:so we have
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so the conjugate of is
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2.4-i√2/i√2 the conjugate for this is repeat what took place in the problem I just solved...multiplying both top and bottom by the conjugate

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