SOLUTION: Give the polar and exponential forms of each of the complex numbers:
a)6-2j
b)-4j
Algebra.Com
Question 177505: Give the polar and exponential forms of each of the complex numbers:
a)6-2j
b)-4j
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
=\arctan (\frac {b}{a}))
So for 6 - 2j, and , so ^2}=sqrt {40}=2sqrt{10})
=\arctan (\frac {-2}{6})=\arctan(-\frac{1}{3}))
Polar form notation: )
)} + j\sin{{(\arctan(-\frac{1}{3})))} )
Exponential notation:
, so:
So for 6 - 2j, e^{j\arctan(-\frac {1}{3}))
For your other problem: and
Do it the same way, except that arctan(b/a) is because b/a is undefined.
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