SOLUTION: for what value of theta the expression is real and imaginary. 3+2*sin(theta)/1-2*sin(theta)

SOLUTION: for what value of theta the expression is real and imaginary. 3+2sin(theta)/1-2sin(theta)

Question 17687: for what value of theta the expression is real and imaginary.
3+2*sin(theta)/1-2*sin(theta)

Answer by xcentaur(357) (Show Source): You can put this solution on YOUR website!

Now sin(theta) is 1 for 90 degrees
So if theta is 90 we get

Hence it is an imaginary (non-real) value.

Again,for theta=0,sin becomes 0

Which is real.

Hence for given expression we get,
Real values,theta=0 degreees
Imaginary values,theta=90 degrees

Hope this helps,
Prabhat

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